(9x=+2)(3x^2+4x+7)

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Solution for (9x=+2)(3x^2+4x+7) equation: 



(9x=+2)(3x^2+4x+7)

We move all terms to the left:

(9x-(+2)(3x^2+4x+7))=0

We add all the numbers together, and all the variables

(9x-2(3x^2+4x+7))=0



We calculate terms in parentheses: +(9x-2(3x^2+4x+7)), so:

9x-2(3x^2+4x+7)

We multiply parentheses

-6x^2+9x-8x-14

We add all the numbers together, and all the variables

-6x^2+x-14

Back to the equation:

+(-6x^2+x-14)



We get rid of parentheses

-6x^2+x-14=0

a = -6; b = 1; c = -14;
Δ = b2-4ac
Δ = 12-4·(-6)·(-14)
Δ = -335
Delta is less than zero, so there is no solution for the equation

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